What are the solutions to the equation (x-2)^2+3(x-2)-18=0 ?

The solutions to the equation (x-2)^2+3(x-2)-18=0 are x=5,x=-4

Find the zeros of (x-2)^2+3(x-2)-18=0

The zeros of (x-2)^2+3(x-2)-18=0 are x=5,x=-4

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(x - 2)^{2} + 3 (x - 2) - 18 = 0

x = 5, x = - 4

Solution steps

(x - 2)^{2} + 3 (x - 2) - 18 = 0

Expand

(x - 2)^{2} + 3 (x - 2) - 18 : x^{2} - x - 20

x^{2} - x - 20 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 1 \cdot ( - 20 )}{2 \cdot 1}

(- 1)^{2} - 4 \cdot 1 \cdot (- 20) = 9

x_{1, 2} = \frac{- ( - 1 ) \pm 9}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 9}{2 \cdot 1}, x_{2} = \frac{- ( - 1 ) - 9}{2 \cdot 1}

x = \frac{- ( - 1 ) + 9}{2 \cdot 1} : 5

x = \frac{- ( - 1 ) - 9}{2 \cdot 1} : - 4

The solutions to the quadratic equation are:

x = 5, x = - 4

∣ - 7 + 2 ∣

- 1 - 1

1 < x < 3

2 x^{3} + 3 x^{2} - 29 x + 30

3 x^{3} + 81

What are the solutions to the equation (x-2)^2+3(x-2)-18=0 ?
The solutions to the equation (x-2)^2+3(x-2)-18=0 are x=5,x=-4
Find the zeros of (x-2)^2+3(x-2)-18=0
The zeros of (x-2)^2+3(x-2)-18=0 are x=5,x=-4