What is the derivative of 4sin(θ)-θ ?

The derivative of 4sin(θ)-θ is 4cos(θ)-1

What is the first derivative of 4sin(θ)-θ ?

The first derivative of 4sin(θ)-θ is 4cos(θ)-1

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derivative of

4 sin (θ) - θ

4 cos (θ) - 1

Solution steps

\frac{d}{d θ} (4 sin (θ) - θ)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d θ} (4 sin (θ)) - \frac{d}{d θ} (θ)

\frac{d}{d θ} (4 sin (θ)) = 4 cos (θ)

\frac{d}{d θ} (θ) = 1

= 4 cos (θ) - 1

\int_{- 1}^{2} x e^{6 x} d x

3 x^{\frac{5}{2}} + 8 x^{2}

\int \frac{1}{2 π} e^{\frac{x ^{2}}{2}} d x

x \to 3 - lim (ln (x^{2} - 9))

\frac{d}{d x} (sin (x) + x \cdot cos (x))

What is the derivative of 4sin(θ)-θ ?
The derivative of 4sin(θ)-θ is 4cos(θ)-1
What is the first derivative of 4sin(θ)-θ ?
The first derivative of 4sin(θ)-θ is 4cos(θ)-1